BY01 Enzyme Catalase

             The enzyme catalase speeds up the decomposition of Hydrogen Peroxide into water and oxygen as shown here, 2H2O2-------------------*2H2O+O2.
             It is one of the fastest known enzymes and its turnover number is 6 million, which means the number of substrate molecules which one molecule of the enzyme turns to products per minute. This can be demonstrated by putting a piece of liver into a beaker of Hydrogen Peroxide, the fizzing shows a demonstration of the enzyme in action.
             My aim is to examine how the concentration of the substrate hydrogen peroxide affects the enzyme catalase.
             I am going to investigate the effect of varying the substrate concentration on enzyme catalase. I am going to use 8 different concentrations and record the time taken to collect 20ml of gas in the gas syringe. I will repeat all the 8 concentrations twice so I can see if they match, spot out any anonymous results and also I can work out the average time it takes to produce 20ml of gas at the certain concentrations. I will vary the concentrations by increasing and decreasing the amounts of Hydrogen Peroxide and water.
             First of all I will ensure I have enough enzyme solution for the whole experiments so the enzyme solution is standardised. With the results I get I will try to work out the ½ Vmax. I will do this experiment at room temperature so the enzymes get enough kinetic energy to collide. I will need 80ml of the enzyme solution because I will use 5ml for all of the experiment and I will do 8 different concentrations and I will repeat this concentrations twice so that is 5x8x2= 80. First of all I will set out the equipment as I will show in the diagram then I will cut some pieces of liver, which is the source of the enzyme. Then I will grind the pieces of liver with the mortar and pestle, which will have sand and Di ionised water (which is water with no H ions in it its PH is neutral). The sand will help cut open the cells of the liver. I will...

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