calculation is shown below.
             Sample Calculation for Calculating Heat Capacity of a Calorimeter:
             Heat Of Hot H20 (lost) = Heat Of Cold H20 (gained) + the Calorimeter
             Heat Of Hot H20 (lost) = SH of H20 x Mass of Water x ∆T
             Heat Of Cold H20 (gained) = SH of H20 x Mass of Water x ∆T
             Specific Heat of H20 (SH) = 4.184 J/g ¡æ
             Ti Cold = 23.1 ¡æTi Hot = 81.4 ¡æTf = 50.3 ¡æ ∆TCold = 50.3 C 23.1 = 27.2 ¡æ∆THot = 50.3 C 81.4 = -31.1 ¡æ
             Heat of Cold H20 = 4.184 J/g ¡æ x 50 g x 27.2 ¡æ = 5690.24 J
             Heat of Hot H20 (lost) = 4.184 J/g ¡æ x 50 g x -31.1 ¡æ = 6506.12 J
             6506.12 J = 5690.24 J + Heat gained by Calorimeter
             Heat gained by Calorimeter = 815.88 J
             Heat Capacity = Heat gained by the Calorimeter ∆TCold= 815.88 J 27.2 ¡æ = 30.0 J/¡æ ( 0.03 kJ/¡æ )
             The two calorimeters used were consistent in their heat absorption which is proven by the results in Table 1. Since cal
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