The task is to find out how many M&M's fit into a certain sized jar to win a competition. This is assuming that all the M&M's are the same size, shape and weight. There are three methods, the first one is to count how many M&M's can fit on the bottom of the jar them count how many layers there are. The second is to find out the area of the jar and an M&M and then see how many times the area of an M&M can go into the jar. The third method is to weigh an M&M and then fill the jar and weigh it minus the jar weight then divided by the weight of a single M&M.
             Twenty-nine (29) M&M's fit in the bottom of the jar and the M&M's go up sixteen (16) layers high. The amount of M&M's in the jar is Twenty Nine times sixteen (base x height) so there would be four hundred and sixty four (464) M&M's in the jar.
             The area of a Circle is found by this formula A= pie x Radius Squared.
             Pie x 3.5cm squared = 38.48 x 18.5 = 711 (The area of the jar)
             Pie x 0.6cm squared = 0.011 x 0.005 = 2.2 (The area of a M&M)
             If the area of the jar (711) is divided by the area of an M&M, (2.2) then the amount of M&M's that could fit into the jar would be 323.
             The M&M's alone weight 600g divided that by 0.89g the weight of an M&M the amount of M&M's in the jar are 647.
             The actual amount of M&M's in the jar were 692 so the best method for finding the amount of M&M's in a jar is the third method weighing them. This is because the second method assumed that the M&M's all had the same area, while the first method was closer to the amount than the second it was also assuming that the bottom area of the jar was the same as every other layer. Therefore, the third method was the best by far, because it didn&apos
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